In this post, I would like to point out that dividing a number by zero doesn’t always raise an exception as is generally taken for granted. The raising of exception depends upon the type of the number being divided by zero.
As the name itself suggests, this exception is raised at run time when the compiler tries to divide a number by zero. But this exception is not raised at all times. For instance, take the code below:
int num1 = 150; int num2 = 0; int result = num1/num2;
The above piece of code, when executed will raise the
But this is not the case when we divide a number of type double with zero. For instance, if you execute the code below, it will not raise any exception and will just execute normally.
double num1 = 15.8 int num2 = 0 double result = num1/num2;
Now, this is not a bug but in fact, a very normal scenario. The result of this division will be “Infinity”, positive infinity, to be precise. the
double type has a property for infinity. This infinity is just like any other number and can also be used in calculations. For instance, the following lines of code can be executed without any compilation errors or run time exceptions.
Console.WriteLine(15 + infinity); //prints infinity Console.WriteLine(15 - infinity); //prints negative infinity Console.WriteLine(infinity * 3); //prints infinity again Console.WriteLine(infinity * 0); //prints NaN Console.WriteLine(infinity / 1023); //prints infinity Console.WriteLine(1281 / infinity); //prints zero Console.WriteLine(infinity + infinity); //prints infinity Console.WriteLine(infinity / infinity); //prints NaN Console.WriteLine(infinity * infinity); //prints infinity
double type provides methods to check if a number is infinity or not. Some of those properties are:
The type also provides properties like:
This can be used in calculations where infinity is being used.
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Hope this helps!